标签: SQL

  • PHP如何正则表达式获取SQL语句中的表名?

    PHP如何正则表达式获取SQL语句中的表名?

    有一个SQL语句集合,里面可能有selectselect ... left joinupdatedeleteinsert

    要从这语句集合中获取到所有的表名,代码如下:

    <?php
    function get_sql_tables($sqlString) {
        $sqlString = str_replace( '`','',trim($sqlString) ).' AND 1=1 ';
        $key = strtolower(substr($sqlString, 0, 6));
        if( $key === 'select' ){
            $tmp = explode('where' , strtolower( trim( $sqlString ) ) );
            $tmp = explode('from',$tmp[0]);
            if ( strpos($tmp[1],',') !== false && ! stristr( $tmp[1],'select')){
                $tmp = explode( ',' , $tmp[1] );
                foreach( $tmp as $k => $v ){
                    $v = trim( $v );
                    if( strpos( $v , ' ') !== false ){
                        $tv = explode(' ' , $v);
                        $return[] = $tv[0];
                    }
                }
                return $return;
            }else{
                $expression = '/((SELECT.+?FROM)|(LEFT\\s+JOIN|JOIN|LEFT))[\\s`]+?(\\w+)[\\s`]+?/is';
            }
        }else if( $key === 'delete' ){
            $expression = '/DELETE\\s+?FROM[\\s`]+?(\\w+)[\\s`]+?/is';
        }else if( $key === 'insert' ){
            $expression = '/INSERT\\s+?INTO[\\s`]+?(\\w+)[\\s`]+?/is';
        }else if( $key === 'update' ){
            $tmp = explode( 'set' , strtolower( str_replace('`','',trim( $sqlString ) ) ) );
            $tmp = explode( 'update' , $tmp[0] );
            if ( strpos($tmp[1] , ',' ) !== false && ! stristr( $tmp[1] , 'update' ) ){
                $tmp = explode( ',' , $tmp[1] );
                foreach( $tmp as $k => $v ){
                    $v = trim( $v );
                    if( strpos( $v , ' ') !== false ){
                        $tv = explode(' ' , $v);
                        $return[] = $tv[0];
                    }
                }
                return $return;
            }else{
                $expression = '/UPDATE[\\s`]+?(\\w+)[\\s`]+?/is';
            }
        }
        preg_match_all($expression, $sqlString, $matches);
        return array_unique(array_pop($matches));
    }

    使用姿势:

    <?php
    $sql = "select count(*) as count from order as a left join user as b on a.user_id = b.user_id where a.title like '%老季%'";
    var_dump(get_sql_tables());#输出结果:order和user
    $sql = "select * from T_5 a, T_6 b , T_7 c where a.id=b.id";
    var_dump(get_sql_tables());#输出结果:Array ( [0] => T_5 [1] => T_6 [2] => T_7 )


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